Free tool

BO1 / BO3 / BO5 Series Win Probability Calculator

A per-map edge compounds over a series. Enter a map win probability and this returns the BO1, BO3 or BO5 series probability, the fair series price, and the full correct-score split — or set each map separately to price a veto.

Series format
Series win
64.80%
Series loss
35.20%
Fair series price
1.54
Correct scoreProbability
2–036.00%
2–128.80%
1–219.20%
0–216.00%
Odds format

Enter a series price to see the per-map win rate it corresponds to.

Assumes each map is independent and equally likely to go your way. Real series aren’t quite like that: the veto steers a series onto maps each side picked, so “set each map separately” is the more honest mode when you have a view on the map pool. This is arithmetic on your own numbers, not a forecast.

Informational and educational only. 18+. This tool performs arithmetic on figures you enter; it does not recommend any outcome and makes no prediction.

Reference

The same edge, three formats

Read down a row and you get the single most useful fact about series formats: a small per-map edge is nearly invisible over one map and substantial over five. Every figure is computed by the code the calculator runs.

Win % on a mapBO1 seriesBO3 seriesBO5 series
50%50.0%50.0%50.0%
55%55.0%57.5%59.3%
60%60.0%64.8%68.3%
65%65.0%71.8%76.5%
70%70.0%78.4%83.7%
80%80.0%89.6%94.2%

This is why format matters so much in Counter-Strike. Group stages built on BO1s produce upsets that the same teams would rarely produce in a BO3, and a BO5 final is the most favourite-friendly format the game plays. None of that is a claim about any particular team — it is what the arithmetic does to any edge you put into it.

The one thing it cannot see is the veto, which deliberately steers a series onto maps each side chose. That is what the per-map mode is for; our study of what teams actually ban is a reasonable starting point for the numbers to put in it.

FAQ

Series and format questions

How do you work out a BO3 win probability from a map win probability?
A team winning each map with probability p wins a BO3 with probability p²(3 − 2p): it can win 2–0, or drop either of the first two maps and win the decider. At p = 60% that comes to 64.8%. For a BO5 it is p³(10 − 15p + 6p²), or 68.3% at the same per-map rate.
Why does a BO3 favour the better team more than a BO1?
Because more maps mean less variance. A single map is close to a coin flip even between mismatched teams; over three or five, the better side has more chances for its edge to show. A 60% map team wins 60% of BO1s but 64.8% of BO3s and 68.3% of BO5s — the same edge, compounded.
Does this account for the map veto?
Only if you tell it to. The simple mode assumes the same win probability on every map, which the veto makes untrue — each side picks maps it is better on. "Set each map separately" is the honest mode when you have a view on the map pool: give each map in the series its own probability and the maths handles the rest.
What are the assumptions?
Each map is treated as independent, and in simple mode as equally likely to go your way. Real series may not be independent — momentum, and reading an opponent between maps, are both plausible. This is arithmetic on the numbers you supply, not a forecast, and it should be read that way.
What is a fair series price?
One divided by the series win probability, with no margin in it. A real quoted price will always be shorter than that, because the margin sits on top — you can measure that gap with the vig calculator, or remove it with the no-vig calculator.

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